2(-1-3y)^2-6y-1-3y=11

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Solution for 2(-1-3y)^2-6y-1-3y=11 equation: 



2(-1-3y)^2-6y-1-3y=11

We move all terms to the left:

2(-1-3y)^2-6y-1-3y-(11)=0

We add all the numbers together, and all the variables

2(-3y-1)^2-6y-3y-1-11=0

We add all the numbers together, and all the variables

-9y+2(-3y-1)^2-12=0

We move all terms containing y to the left, all other terms to the right

-9y+2(-3y-1)^2=12

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